Chapter 1: Algebra Review

Chapter 1 Review Problems

Review Problems

1. Use the rules of exponents to simplify the following. Write your answer using only positive exponents. Assume all variables represent non-zero numbers.

a. [latex]\frac{4y^3}{12y^7}[/latex]

b. [latex]\bigg(m^{-2} \bigg)^3[/latex]

c. [latex]\bigg( xyz \bigg)^8[/latex]

d. [latex]\bigg(2xy^{-3}z^0 \bigg)^3[/latex]

e. [latex]\bigg(5x^3\bigg) \bigg(-7x^5 \bigg)[/latex]

f. [latex]\sqrt[4]{(4ab^2)^4 (b^{-3})^{-2} }[/latex]

 

2. Write the equation of the line that is parallel to and has y-intercept [latex]y = 1.5x-11[/latex] at [latex]y = 3[/latex].

3. Write the equation of the line that passes through the points [latex](1, 5)[/latex] and [latex](3, 11).[/latex]

4. A coffee supplier finds that it costs [latex]\$850[/latex] to roast and package [latex]100[/latex] pounds of coffee in a day and [latex]\$2850[/latex] to produce [latex]500[/latex] pounds of coffee in a day. Assume that the cost function is linear. Express the cost as a function of the number of pounds of coffee they produce each day.

5. Factor [latex]y^5-6y^4+9y^3[/latex].

6. Factor [latex]a^4-5a^2-36[/latex].

7. The two points [latex](-3, \frac{5}{8} )[/latex] and [latex](2,20)[/latex] both lie on the graph of a function.

  1. Find the formula [latex]y = g(x)[/latex] for if it is a linear function.
  2. Find the formula [latex]y = g(x)[/latex] for if it is of the form [latex]g(x) = Ca^x[/latex].

8. An object is thrown into the air. Its height in feet above the ground [latex]t[/latex] seconds later is given by [latex]h(t) = -16t^2+30t+25[/latex].

  1. Find the time when the object reaches its maximum height.
  2. How high does it get?
  3. When does it land?
  4. The graph of [latex]y = h(t)[/latex] is a parabola. What is the physical meaning of the [latex]y[/latex]-intercept of this parabola? (That is, what does the [latex]y[/latex]-intercept of the parabola tell us about the object?)

 

9. Suppose [latex]\bigg( u \circ v \bigg) (x) = \frac{1}{x^2}+1[/latex] and [latex]\bigg( v \circ u \bigg) (x) = \frac{1}{(x+1)^2}[/latex]. Find possible formulas for [latex]u(x)[/latex] and [latex]u(x)[/latex].
10. Suppose [latex]f(x) = x^2-2x[/latex]:

  1. Compute [latex]\frac{f(x)-f(3)}{x-3}[/latex]. Simplify your answer.
  2. In English, what is the meaning of your answer to part a?
  3. Graphically, what is the meaning of your answer to part a?

 

10. Here is the graph of [latex]y = f(x)[/latex]. Use this graph to sketch the graph on graph paper of [latex]y = -3f(x-2)[/latex]. Be careful and neat, and remember to label your graph. Briefly explain what you did to find the graph.

image

 

11. In [latex]2000[/latex], the number of people infected by a virus was [latex]P_0[/latex]. Due to a new vaccine, the number of infected people has decreased by 14% each year since 2000.

  1. Find a formula for [latex]P = f(n)[/latex], the number of infected people [latex]n[/latex] years after [latex]2000[/latex].
  2. When will there be (or when were there) just half as many people infected as there were in [latex]2000[/latex]?

12. Here is the graph of an exponential or logarithmic function.

image
  1. Is this an exponential function with base [latex]b > 1[/latex], an exponential function with [latex]0 b 1[/latex], or a logarithmic function with base [latex]b > 1[/latex]?
  2. What is the value of [latex]b[/latex] (the base) for this graph? How do you know?

Brief Answers to Selected Exercises

1.

  1. [latex]\frac{4y^3}{12y^7}[/latex]
  2. [latex]\bigg( 2xy^{-3} z^0 \bigg) ^3 = \frac{8x^3}{y^9}[/latex]
  3. [latex]\sqrt[4]{(4ab^2)^4(b^{-3})^{-2}}= 4ab^{\frac{7}{2}}[/latex]

3.
[latex]y= 3x+2[/latex]

4.
[latex]C(n) = 5n+350[/latex], where [latex]C[/latex] is the cost in dollars and [latex]n[/latex] is the number of pounds of coffee produced.

5. [latex]y^3(y-3)^2[/latex]

7.

  1. [latex]g(x) = \frac{31}{8}x - \frac{49}{4}[/latex]
  2. [latex]g(x) = 5.2^x[/latex]

9. [latex]u(x) = x+1 \ ; \ v(x) = \frac{1}{x^2}[/latex]

11. The graph is the same basic shape, but it is upside down, 3 times as tall, and shifted 2 units to the right. The four labeled points are now [latex](-1, -6), (0, 3), (5, -12[/latex]), and [latex](9, 0)[/latex].

12.

  1. This is exponential decay, so an exponential function with [latex]0 b 1[/latex].
  2. (You have to estimate here. Your answer might be different from mine.) It looks to me as if when [latex]x = -1[/latex], [latex]y[/latex] is about [latex]2.8[/latex], so I will guess that this is [latex]y = \frac{1}{e^x} = e^{-x}[/latex].

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